2(2x^2-5)+12=3x^2+5

Solution for 2(2x^2-5)+12=3x^2+5 equation:

Simplifying
2(2x2 + -5) + 12 = 3x2 + 5

Reorder the terms:
2(-5 + 2x2) + 12 = 3x2 + 5
(-5 * 2 + 2x2 * 2) + 12 = 3x2 + 5
(-10 + 4x2) + 12 = 3x2 + 5

Reorder the terms:
-10 + 12 + 4x2 = 3x2 + 5

Combine like terms: -10 + 12 = 2
2 + 4x2 = 3x2 + 5

Reorder the terms:
2 + 4x2 = 5 + 3x2

Solving
2 + 4x2 = 5 + 3x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x2' to each side of the equation.
2 + 4x2 + -3x2 = 5 + 3x2 + -3x2

Combine like terms: 4x2 + -3x2 = 1x2
2 + 1x2 = 5 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
2 + 1x2 = 5 + 0
2 + 1x2 = 5

Add '-2' to each side of the equation.
2 + -2 + 1x2 = 5 + -2

Combine like terms: 2 + -2 = 0
0 + 1x2 = 5 + -2
1x2 = 5 + -2

Combine like terms: 5 + -2 = 3
1x2 = 3

Divide each side by '1'.
x2 = 3

Simplifying
x2 = 3

Take the square root of each side:
x = {-1.732050808, 1.732050808}